0.6x^2+1.4x-4.8=0

Solution for 0.6x^2+1.4x-4.8=0 equation:

0.6x^2+1.4x-4.8=0

a = 0.6; b = 1.4; c = -4.8;
Δ = b2-4ac
Δ = 1.42-4·0.6·(-4.8)
Δ = 13.48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.4)-\sqrt{13.48}}{2*0.6}=\frac{-1.4-\sqrt{13.48}}{1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.4)+\sqrt{13.48}}{2*0.6}=\frac{-1.4+\sqrt{13.48}}{1.2}
$